Question

find the maximum number which will divide 398 and 436 leaving remainder 11 and 15 respectively​

Answer 1

Answer:

The number 398, 436 and 542 which when divides by a positive integers leaves remainder as 7, 11, and 15 respectively . → Clearly, the required number divides ( 398 - 7 ) = 391 , ( 436 - 11 ) = 425, and ( 542 - 15 ) = 527 exactly .

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Answer 2

Step-by-step explanation:

Answer :-

→ 17 .

Step-by-step explanation :-

We have ,

→ The number 398, 436 and 542 which when divides by a positive integers leaves remainder as 7, 11, and 15 respectively .

→ Clearly, the required number divides ( 398 - 7 ) = 391 , ( 436 - 11 ) = 425, and ( 542 - 15 ) = 527 exactly .

•°• Required number = HCF( 391, 425, 527 ) .

Now,

→ 391 = 17 × 23 ,

→ 425 = 5² × 17 ,

→ 527 = 17 × 31 .

\therefore∴ HCF( 391, 425, 527 ) = 17 .

Hence, the required number is 17 .

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