Question

Find the maximum Range​

Answer 1

A launch angle of 45 degrees displaces the projectile the farthest horizontally. This is due to the nature of right triangles. Additionally, from the equation for the range : We can seethat the range will be maximum when the value of is the highest (i.e. when it is equal to 1).

Answer 2

Explanation:

$to \: find \: maximum \: range \: of \: a \: particle \\ \\ we \: use \: formula.... \frac{ {x}^{2} \sin(2 \beta ) }{g} \\ \\ where \: \: x = initial \: velocity \: of \: a \: particle \\ \\ g = gravittional \: constant(10 \: \frac{m}{ {sec}^{2} } )$

hope it helps.........✌✌