Question

find the maximum range of cannon stone projected with a velocity of 16m/s​

Answer 1

Answer:

Horizontal Range R=

g

u

2

sin2θ

For maximum horizontal range θ=45

0

or, R

max

=

g

u

2

; where u is the muzzle velocity of the shell

∴1600m=

10m/s

2

u

2

∴u=400m/s