Question

Find the maximum speed at which a car can take turn round a curve of 30m radius on level road .The coefficient of friction between tyres and road is 0.4

Answer 1

Answer:

937

Explanation:

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Answer 2

Answer:

Explanation:

The centripetal force (F) needed to turn the car is given by,

$F=\frac{mv^{2}}{r}$ ...(1)

where

'r' is the radius of the curve

'$v$' is the maximum speed of the car

'm' is the mass of the car

The centripetal force will be equivalent to the frictional force (f) which is given by,

$f =\mu mg$  ...(2)

where

'μ' is the coefficient of friction.

Using (1) and (2),

$\frac{mv^{2}}{r} = \mu mg$   ...(3)

Rearranging the above equation to obtain the expression for v.

Then,

  $v^{2} = \mu rg\\ v \ = \sqrt{ \mu rg}$ ...(4)

From the question,

r =  $30$ m

g = $10\ m/s^{2}$

$\mu = 0.40$

Substitute all these values into equation (4).

Then,

$v \ = \sqrt{ 0.40\times30\times10}$

   $= \sqrt{ 120}$

   $= 10.95\ m/s$

Maximum speed  =  $10.95\ m/s$