Question

Find the maximum speed at which a car turn round a curve of 36 m radius
on a level road. Given the co-eff. of friction between the tyre and road is 0.53.​

Answer 1

Explanation:

radius of the curvature = 36m

co-eff = 0.53

Acceleration due to gravity =

$10 \frac{m}{ {s}^{2} }$

To find maximum speed

maximum speed,

frictional force given by,

$f = \mu mg$

$where \: f = centepetal \: force \\ \frac{m {v}^{2} }{s} = \mu \: mg \\ cut \: the \: mass \: from \: the \: both \: sides \\ v = \sqrt{ \mu \: gs } \\ \sqrt{0.53 \times 36 \times 10} \\ 159m {s}^{ - 1}$