find the maximum sum of the A. P . 30,27,24,21,18,......
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30,27,24,21,18,.....
a=30 a2=27 a3=24
d = a2 - a
d = 27 - 30
d = -3
sn = n/2[2a + (n-1)d ]
sn = n/2[2(30) + (n-1)-3]
sn = n/2[60 -3n +3 ]
sn = n/2 [63 -3n]
sn = 63n/2 - 3n^2/2
Hence , 63n/2 -3n^2/2 is the maximum sum of the given AP
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