find the maximum sum of the a.p. 30,27,24,21
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Answer:
a=30,d=27-30,n=?
= -3
an=a+(n-1)d
= 30+(n-1)-3
-30=-3(n-1)
n-1=-30/-3
n-1=10
then , n= 11
Sn= n/2 [2a+(n-1)d]
11/2[2×30+(11-1)-3]
11/2 [30]
11×15
165
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