Find the maximum value of 5cosA + 12sinA + 12
Answers
Answered by
0
= 5 * cos 90 + 12 * sin 0 + 12
= 5 * 1 + 12 * 1 + 12
= 5 +12 + 12
= 24 + 5
= 29 ans.
= 5 * 1 + 12 * 1 + 12
= 5 +12 + 12
= 24 + 5
= 29 ans.
Dsnyder:
sorry wrong answer
ok
thanks i try to do it once again my friend helped me actually i dont have it in my portion
KK IT'S OKAY
Answered by
0
5cosA +12sinA + 12
= 13(5/13 cosA +12/13sinA) + 12
Now, for any values of B we can get sinB = 5/13
and we can replace cosB = 12/13.
We see that our assumption is right because we satisfy the condition sin^2B + cos^2B = 1
so we get 13(sinBcosA +cosBsinA) + 12...
= 13(5/13 cosA +12/13sinA) + 12
Now, for any values of B we can get sinB = 5/13
and we can replace cosB = 12/13.
We see that our assumption is right because we satisfy the condition sin^2B + cos^2B = 1
so we get 13(sinBcosA +cosBsinA) + 12...
full answer???
Similar questions