Find the maximum value of u=x+2y+3z on the plane x+y+z=3
Answers
Answered by
0
Step-by-step explanation:
Correct option is B)
x+y+z=1⇒2.
2
x
+3.
3
y
+4.
4
z
=1
Using weighted mean
9
2.(
2
x
)+3.(
3
y
)+4.(
4
z
)
≥((
2
x
)
2
(
3
y
)
3
(
4
z
)
4
)
9
1
(
9
1
)
9
≥
2
10
3
3
x
2
y
3
z
4
⇒x
2
y
3
z
4
≤
3
15
2
10
Similar questions