find the mean 1st 50 even number
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First even number = 2
50th even number = 100
sum of 50 even number = 2 + 100 / 2 × 50
= 102 /2 × 50
= 51 × 50
= 2550
Mean = 2550/50
= 51
50th even number = 100
sum of 50 even number = 2 + 100 / 2 × 50
= 102 /2 × 50
= 51 × 50
= 2550
Mean = 2550/50
= 51
Answered by
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Hi ,
2 , 4 , 6 , ....., 100 are first 50 even
numbers .
These are in Arithmetic progression.
First term = a = 2
common difference ( d ) = a2 - a1
d = 4 - 2 = 2
Number of terms = n = 50
nth term = an = 100
Sum of n terms = Sn = n/2 [ a + an ]
S50 = 50/2 [ 2 + 100 ]
= 25 × 102
= 2550 ---( 1 )
Mean = Sn / n
= 2550/50
= 51
I hope this helps you.
: )
2 , 4 , 6 , ....., 100 are first 50 even
numbers .
These are in Arithmetic progression.
First term = a = 2
common difference ( d ) = a2 - a1
d = 4 - 2 = 2
Number of terms = n = 50
nth term = an = 100
Sum of n terms = Sn = n/2 [ a + an ]
S50 = 50/2 [ 2 + 100 ]
= 25 × 102
= 2550 ---( 1 )
Mean = Sn / n
= 2550/50
= 51
I hope this helps you.
: )
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