Find the mean deviation about the mean for the data in: 38, 70, 48, 40, 42, 55, 63, 46, 54, 44
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Solution :
Given data :
38 , 70, 48 , 40 ,42 , 55 , 63 , 46 ,
54 , 44
Let the assumed mean is A = 50
Arithmetic mean = A+[sigma xi - A]/N
= 50 + [(38-50)+(70-50)+(48-50)
+(40-50)+(42-50)+(55-50)+(63-50)
+(46-50)+(54-50)+(44-50)]/10
= 50 +[-12+20-2-10-8+5+13-4+4-6]/10
= 50 + ( 42 - 42 )/10
= 50
Therefore,
Mean = 50
••••
Given data :
38 , 70, 48 , 40 ,42 , 55 , 63 , 46 ,
54 , 44
Let the assumed mean is A = 50
Arithmetic mean = A+[sigma xi - A]/N
= 50 + [(38-50)+(70-50)+(48-50)
+(40-50)+(42-50)+(55-50)+(63-50)
+(46-50)+(54-50)+(44-50)]/10
= 50 +[-12+20-2-10-8+5+13-4+4-6]/10
= 50 + ( 42 - 42 )/10
= 50
Therefore,
Mean = 50
••••
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