find the mean deviation about the median for the following data 6,7,10,12,13,4,8,12
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Given data 6,7,10,12,13,4,12,16
first of all arrange data in ascending order
4,6,7,10,12,12,13,16
Here observe that no of observations is even i.e. n=8
So average of
Median is
2
n
th term and (
2
n
+1)
th
term
Median =
2
2
n
th
term+(
2
n
+1)
th
term
=
2
2
8
th
term+(
2
8
+1)
th
term
=
2
4
th
term+5
th
term
=
2
10+12
=
2
22
=11
(M) median =11
Now, we calculate mean deviation about median
we know that mean deviation about median =
8
∑(x
i
−M)
M.D(M)=
8
∣4−11∣+∣6−11∣+∣7−11∣+∣10−11∣+∣12−11∣+∣12−11∣+∣13−11∣+∣16−11∣
=
8
7+5+4+1+1+1+2+5
we know ∣−x∣=x∣+x∣=x
=
8
26
=3.25
mean deviation about median (M.D(M))=3.25
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