Question

Find the mean deviation ci) from mean (in) from median for the following data: Marks 20 18 16 14 12 10 8 6 No. of students 4 9 18 27 25 14 1 how meadian 2.24 ..​

Answer 1

Answer:

Marks f

i

Cumulative frequency x

i

∣x

i

−M∣ f

i

∣x

i

−M∣

0-10 6 6 5 22.86 137.16

10-20 8 14 15 12.86 102.88

20-30 14 28 25 2.86 40.04

30-40 16 44 35 7.14 114.24

40-50 4 48 45 17.14 68.56

50-60 2 50 55 27.14 54.28

Total 50 517.32

Here, N=50

2

N

=

2

50

=25

Since, 25 occurs in the cumulative frequency 25.

So, median class is 20−30.

Median M=l+

f

m

2

N

−C

f−1

×h

=20+

14

25−14

×10

M=20+

14

110

=27.86

Mean deviation about median =

∑f

i

∑f

i

∣x

i

−M∣

=

50

517.32

=10.35

Step-by-step explanation:

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