find the mean deviation from the median for of the following set of observations.68,57,42,49,55
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Answered by
1
Answer:
Arranging the given data in an ascending order, we get :
36, 42, 45, 46, 48, 50, 51, 53, 60, 72.
Here n=10, which is even.
∴ median=12.{n2th observation+(n2+1)th observation}
=12(5th observation + 6th observation)
=12(48+50)=982=49.
Thus, M=49.
The values of (xi−M) are
−13,−7,−4,−3,−1,1,2,4,11,23.
∴ Σi=110|xi−M|=(13+7+4+3+1+1+2+4+11+23)=69
⇒ MD(M)=Σi=110|xi−M|10=6910=6.9.
Answered by
1
Answer:
54.2
Step-by-step explanation:
let mean =50
then by using deviation
+18+7-8-1+5=21
mean=50+21/5=54.2
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