Question

find the mean median and mode of 7,10,7,5,9,10​

Answer 1

Answer:

5,7,7,9,10,10

Step-by-step explanation:

the odd number of observation six is even hence the correct

Answer 2

★ How to do :-

Here, we are given with six observations in a data in which we are asked to find the mean, median and mode. Firstly, we'll find the mean. To find the mean, we have a separate formula which can be used here. We use that formula and can find the mean. Next, we'll find the median. To find the median, we have two formulas by which we can solve the median of the data. The first formula is for even observations and the other for odd observations. Finally, we'll find the mode of the data. To find the mode, we don't have any formula. But, the mode is the most occuring or repeating observation in the data. There can be more than one mode also. So, let's solve!!

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➤ Solution :-

Mean :-

${\sf \longrightarrow \underline{\boxed{\sf Mean = \dfrac{Sum \: of \: all \: observations}{Number \: of \: observations}}}}$

Substitute the given values.

${\tt \leadsto \dfrac{7 + 10 + 7 + 5 + 9 + 10}{6}}$

Add all the values in the numerator.

${\tt \leadsto \dfrac{24 + 24}{6}}$

Add the two remaining values in numerator.

${\tt \leadsto \dfrac{48}{6}}$

Simplify the fraction to get the value of mean.

${\tt \leadsto \sf Mean = \cancel \dfrac{48}{6} = 8}$

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Ascending order :-

5, 7, 7, 9, 10, 10.

Now, let's find the median.

Median :-

${\sf \longrightarrow \underline{\boxed{\sf {Median}_{Even \: observations} = \dfrac{n}{2} + 1th \: \: term}}}$

Substitute the value of n.

${\tt \leadsto \dfrac{6}{2} + 1th \: \: term}$

Simplify the fraction.

${\tt \leadsto 3 + 1th \: \: term}$

Add the values to get the answer.

${\tt \leadsto 4th \: \: term}$

In the ascending order, we can see that the 4th term is 9. So,

${\tt \leadsto \sf Median = 9}$

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Now, let's find the mode.

Mode :-

The mode is considered as the most occuring observation.

In the given data, we can see that the number 7 and 10 are repeating two times. So,

${\tt \leadsto \sf Mode = 7 \: and \: 20}$

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$\boxed{ \begin{array}{cc} \sf \dag Answers \\ \\ \bigstar \sf \: Mean = 8 \\ \\ \bigstar \: \sf Median = 9 \\ \\ \bigstar \sf \: Mode = 7 , 20 \end{array}}$