Find the mean , median and mode of the following no:s
10, 9, 3, 3 , 6, 10 , 4 , 3 , 5 ,1 , 9 , 1, 9 ,5 , 9
Answers
Answered by
2
Mean (xbar)
Mean = sigma xi /n
sigma xi = sum of all the observations.
n= number of total observations.
= 10+9+3+3+6+10+4+3+5+1+9+1+9+5+9/ 15
= 87/15
= 5.8
A.M. is 5.8
Median (M)
Arrange the data in ascending or descending order,
1,1,3,3,3,4,5,5,6,9,9,9,9,10,10
Here is odd number of observation,
So formula for median is
= (n+1)/2 th observation
= (15+1)/2th observation
= 16/2th observation
= 8th observation
= 5
So, 5 is our median.
Mode(Z)
Most repeated observation
Here 9 observation appears 4 times.
So,
Mode (Z) = 4
mean = 5.8,
Median (M) = 5
Mode (Z) = 4
Mean = sigma xi /n
sigma xi = sum of all the observations.
n= number of total observations.
= 10+9+3+3+6+10+4+3+5+1+9+1+9+5+9/ 15
= 87/15
= 5.8
A.M. is 5.8
Median (M)
Arrange the data in ascending or descending order,
1,1,3,3,3,4,5,5,6,9,9,9,9,10,10
Here is odd number of observation,
So formula for median is
= (n+1)/2 th observation
= (15+1)/2th observation
= 16/2th observation
= 8th observation
= 5
So, 5 is our median.
Mode(Z)
Most repeated observation
Here 9 observation appears 4 times.
So,
Mode (Z) = 4
mean = 5.8,
Median (M) = 5
Mode (Z) = 4
aqibshaikh:
Hope its helpful to u
Answered by
1
mean
=10+9+3+3+6+10+4+3+5+1+9+1+9+5+9=87
=87/15
=5.8
median
data in ascending order= 1,1,3,3,3,4,5,5,6,9,9,9,9,10,10
=(15+1)/2
=8th
= 5
mode is the no which occurs for the maximum no.of times
9
=10+9+3+3+6+10+4+3+5+1+9+1+9+5+9=87
=87/15
=5.8
median
data in ascending order= 1,1,3,3,3,4,5,5,6,9,9,9,9,10,10
=(15+1)/2
=8th
= 5
mode is the no which occurs for the maximum no.of times
9
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