Question

find the mean ,median and mode of the following set of numbers 1,1,2,4,5,7,8,12,1,5,​

Answer 1

$mean \: = \: \frac{sum \: of \: observations}{no. \: of \: observations}$

Mean = 1+1+2+4+5+7+8+12+15/10 = 5.5

Mean = 1+1+2+4+5+7+8+12+15/10 = 5.5Median =

Mean = 1+1+2+4+5+7+8+12+15/10 = 5.5Median = $median \: = \frac{1}{2}(( \frac{n}{2} )th \: observation+( \frac{n}{2} + 1)th \: observation)$

Mean = 1+1+2+4+5+7+8+12+15/10 = 5.5Median = $median \: = \frac{1}{2}(( \frac{n}{2} )th \: observation+( \frac{n}{2} + 1)th \: observation)$When terms are even.

Mean = 1+1+2+4+5+7+8+12+15/10 = 5.5Median = $median \: = \frac{1}{2}(( \frac{n}{2} )th \: observation+( \frac{n}{2} + 1)th \: observation)$When terms are even.Hence median = 5th + 6th term/2

Mean = 1+1+2+4+5+7+8+12+15/10 = 5.5Median = $median \: = \frac{1}{2}(( \frac{n}{2} )th \: observation+( \frac{n}{2} + 1)th \: observation)$When terms are even.Hence median = 5th + 6th term/2 = 5+7/2

Mean = 1+1+2+4+5+7+8+12+15/10 = 5.5Median = $median \: = \frac{1}{2}(( \frac{n}{2} )th \: observation+( \frac{n}{2} + 1)th \: observation)$When terms are even.Hence median = 5th + 6th term/2 = 5+7/2 = 6

Mean = 1+1+2+4+5+7+8+12+15/10 = 5.5Median = $median \: = \frac{1}{2}(( \frac{n}{2} )th \: observation+( \frac{n}{2} + 1)th \: observation)$When terms are even.Hence median = 5th + 6th term/2 = 5+7/2 = 6Mode = 1

Mean = 1+1+2+4+5+7+8+12+15/10 = 5.5Median = $median \: = \frac{1}{2}(( \frac{n}{2} )th \: observation+( \frac{n}{2} + 1)th \: observation)$When terms are even.Hence median = 5th + 6th term/2 = 5+7/2 = 6Mode = 1(the term which occurs the maximum number of times)