find the mean ,median and the mode of 12,24,24,12,30and 12
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Answer:
find the mean ,median and the mode of 12,24,24,12,30and 12
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Solution :
(i) 12, 24, 24, 12, 30 and 12
Mean = \frac{Sum\ of\ all\ observations\ }{No.\ of\ observations}
=\frac{(12+24+24+12+30+12)}{6}
=\frac{114}{9}
=19
∴ Mean =19
Numbers are 12, 24, 24, 12, 30 and 12
Most frequently occuring term = 12
∴ Mode = 12
Ascending order = 12, 12, 12, 24, 24, 30
Number of terms = 6 (even)
Median =\frac{1}{2}\left\{\frac{n}{2}th\ term\ +\ \left(\frac{n}{2}+1\right)th\ term\ \right\}
=\frac{1}{2}\left\{\frac{6}{2}th\ term\ +\ \left(\frac{6}{2}+1\right)th\ term\ \right\}
=\frac{1}{2}\left\{3^{rd}\ term\ +4^{th}\ term\ \right\}
=\frac{1}{2}\left\{12+24\right\}
=\frac{1}{2}\times36
=18
∴ Median =18
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