Question

Find the mean, medium, mode from the following frequency distribution: 8,9,10,11,12,13

Answer 1

Step-by-step explanation:

mode is 13 as it is the highest occuring frequency

median : number of observation :6

(n/2 +n+1/2)/2

(6/2 +6+1/2)/2

3 +4/2 th observation which is 10+11/2 =21/2 =10.5

mean : sum of all observation/total no. of observation

8+9+10+11+12+13/6 = 63 /6 =10.5

Answer 2

Answer:

Step-by-step explanation:

Mean=total value of number/there total

Mean =8+9+10+11+12+13/6

M=63/6

M=10•5

Medium=the number(s) which I in the middle

Data have already been arranged in ascending order 8,9,10,11,12,13

Our middle numbers are 10 and 11

We find there sum and divide by 2 10+11/2

21/2=10•5

Medium is 10•5

Mode is the data which repeat mostly.

In the data given we don't have such number so we don't have mode.

Hope it's helpful

Thanks