find the mean of cubes of first n even natural numbers
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Answer:
We know that sum of cubes of first n natural numbers is = (n(n+1)/2)2.
Sum of cube of first n even natural numbers
23 + 43 + 63 + ……… + (2n)3
Even Sum = 23 + 43 + 63 + .... + (2n)3
if we multiply by 23 then
= 23 x (13 + 23 + 32 + .... + (n)3)
= 23 + 43 + 63 + ......... + (2n)3
= 23 (n(n+1)/2)2
= 8(n(n+1))2/4
= 2(n(n+1))2
Step-by-step explanation:
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Step-by-step explanation:
We know that sum of cubes of first n natural numbers is = (n(n+1)/2)^2. Attention reader!
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