Question

find the mean of first 5 multiples of 12

Answer 1

Step-by-step explanation:

First 5 multiples of 12 are :-

12 , 24 , 36 , 48 and 60

Since,

n = 5

Mean= Sum of observations ÷ No. of observations

Mean = 12 + 24 + 36 + 48 + 60 /5

= 180 /5

= 36

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Answer 2

Answer:

The mean of first 5 multiples of 12 is 36.    

Step-by-step explanation:

The first 5 multiples of 12 is-

12, 24, 36, 48 and 60.

$Mean = \dfrac{Sum\ of \ numbers}{Total \ numbers}$

                = $\dfrac{12+24+36+48+60}{5}$

                = $\dfrac{180}{5}$

Mean = 36        

Hence, the mean of first 5 multiples of 12 is 36.  

     OTHER METHOD

We can solve this problem by Arithmetic Progression.

Let first term of A.P. = 12

Same difference = 12

Because numbers are the multiples of 12.

We know that-

The sum of n terms of A.P.-

$S_{n}=\dfrac{n}{2}[2a+(n-1)d]$

So, sum of first 5 term-

$S_{5} = \dfrac{5}{2}[2 \times12 +(5 - 1)\times12]$

                = $\dfrac{5}{2}[24 + 4\times12]$

                = $\dfrac{5}{2}[24 + 48]$

                = $\dfrac{5}{2}\times72$

                = 5 × 36

$S_{5} = 180$

Mean of 5 multiples = $\dfrac{sum \ of \ five \ numbers}{5}$

                                 = $\dfrac{180}{5}$

Mean of 5 multiples = 36

Hence, the mean of first 5 multiples of 12 is 36.