Question

Find the mean of following data: 1^2,2^2,3^2,........20^2

Answer 1

${1}^{2} + {2 }^{2} + .............. + {x}^{2}$

formula for it is

$x(x + 1)(2x + 1) \div 6$

then solve it we get

$20 \times 21 \times 41 \div 6$

==>. 2870

Answer 2

Step-by-step explanation:

I can't seem to understand whether this is an addition problem or finding the mean. If you want the sum of all those exponents (1+4+9+16+25+36+49+64+81+100+121+144+169+196+225+256+289+324+361+400=2870) it would just be one number. You need multiple numbers for a mean. The mean of all 20 addends would be 143.5.

(mark me as brainilest please...)