Find the mean of following data using of step-deviation.. Class 5-15,15-25,25-35,35-45,45-55,55-65,6575: frequency: 6,10,16,15,24,8,7
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Let us choose a = 40, h = 10, then `d_i = x_i – 40 and u_i =(x_i-40)/10`
Using step-deviation method, the given data is shown as follows:
Class Frequency `(f_i)` Class mark `(x_i)` `d_i = x_i` – 40 `u_i = (x_i−40)/10`
5 – 15 6 10 -30 -3
15 – 25 10 20 -20 -2
25 – 35 16 30 -10 -1
35 – 45 15 40 0 0
45 – 55 24 50 10 1
55 – 65 8 60 20 2
65 – 75 7 70 30 3
Total `Ʃ f_i` = 86
The mean of the data is given by,
x = a+ `((sum _i f_i u_i)/(sum _i f_i)) xx h`
= 40 + `7/86 xx 10`
=`40+ 70 / 86`
= 40 +0.81
= 40.81
Step-by-step explanation:
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