Question

Find the mean of root 27, root 48, and root 75

Answer 1

$mean = sum \: of \: all \: observation \div no. \: of \: observations$

Answer 2

Answer:

$Required \: mean = 4\sqrt{3}\: Or \: \sqrt{48}$

Step-by-step explanation:

$Given \: terms \: \sqrt{27},\sqrt{48}\:and \: \sqrt{75}$

$\sqrt{27}=\sqrt{3\times 3\times 3} = 3\sqrt{3}$

$\sqrt{48}=\sqrt{4\times 34\times 3} = 4\sqrt{3}$

$\sqrt{75}=\sqrt{5\times 5\times 3} = 5\sqrt{3}$

$\boxed {Mean = \frac{ sum \:of \: the \: terms }{Number \: of \: terms }}$

$Mean = \frac { \sqrt{27}+\sqrt{48}+\sqrt{75}}{3}\\=\frac{ 3\sqrt{3}+4\sqrt{3}+5\sqrt{3}}{3}\\=\frac{(3+4+5) \sqrt{3}}{3}\\=\frac{12\sqrt{3}}{3}\\=4\sqrt{3}$

Therefore.,

$Required \: mean = 4\sqrt{3}\: Or \: \sqrt{48}$

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