Question

Find the mean of the following distribution table class interval 5–15 15―25 25―35 35―45 45―55 55 ―65 frequency are 6 11 21 23 14 5

Answer 1

$\left\begin{array}{|c|c|c|c|}\cline{1-4}\textbf{Interval}&\textbf{Midpoint(x)}&\textbf{Frequency(f)}&fx\\\cline{1-4}5-15&10&6&60\\15-25&20&11&220\\25-35&30&21&6300\\35-45&40&23&920\\45-55&50&14&700\\55-65&60&5&300\\\cline{1-4}&&80&2830\\\cline{1-4}\end{array}\right$

$\textbf{From the table, we get}$

$\Sigma{f}=80$

$\Sigma{fx}=2830$

$\text{Using the formula}$

$\boxed{\textbf{Mean= \bf\displaystyle\frac{\Sigma{fx}}{\Sigma{f}} }}$

$\text{Mean= \displaystyle\frac{2830}{80} }$

$\text{Mean= \displaystyle\frac{283}{8} }$

$\textbf{Mean=35.375}$

$\therefore\textbf{The mean of the given distribution is 35.375}$

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If the mean of the following distribution is 10 then find the value of p

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Answer 2

Answer :29

X=20

fx=580

mean=580/20

=29