Find the mean of the following distribution.
x 5 10 15 20 25
y 4 12 20 28 36
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XMid point (x) Frequency (F) i=class interval width A=22.5 Assumed mean u=ix−A fu0-5 2.5 3 5 22.5 -4 -12 5-10 7.5 5 5 22.5 -3 -15 10 -1512.5 7 5 22.5 -2 -14 15-20 17.5 8 5 22.5 -1 -8 20-25 22.5=A 10 5 22.5 0 0 25-30 27.5 11 5 22.5 1 11 30-35 32.5 14 5 22.5 2 28 35-40 37.5 19 5 22.
5 3 57 40-45 42.5 15 5 22.5 4 60 45-50 47.5 13 5 22.5 5 65 Σf=105 Σfu=172
The formula used for arithmetic mean of grouped data by step deviation method is, X=A+∑f∑fu×i
A= Assumed mean of the given data
∑ = Summation of the frequencies given in the grouped data
∑fu = Summation of the frequencies and deviation of a given mean data
u=i(x−A)
i= Class interval width
X = arithmetic mean
X=22.5+105172×5
=22.5+8.19
=30.69 ≈ 31
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