Math, asked by kesarmann, 1 year ago

find the mean of the following observations : 499,489,504,505,506,496,497,510,508,503,504,490,510,511,507,499,498,497,492,502,500

Answers

Answered by manojkumar975514
0

499 + 489 + 504 + 505 + 506 + 496 + 497 + 510 + 508 + 503 + 504 + 490 + 510 + 511 + 507 + 499 + 498 + 497 + 492 + 502 + 500 \div 2 \: you \: willget \: answer
you will get anwer applying above formula

kesarmann: I didnot get how to if u have a better answer plz suggest
manojkumar975514: add eveything divide by two you'll get use a calculator
kesarmann: OK thanku
manojkumar975514: no problem
Answered by twinkle200260
0
499+489+504+505+506+496+510+508+503+504+490+510+511+507+499+498+497+492+502+500/21=256512
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