Question

Find the mean of the given distribution.​

Answer 1

$\fbox{\LARGE{\underline{\underline{\bf{Solution:}}}}}$

We have,

$\bf{x_i}$ = 1, 2, 3, 4, 5

$\bf{f_i}$ = 4, 5, 8, 10, 3

$\bf{f_ix_i}$ = 4, 10, 24, 40, 15

∴ ∑$\bf{x_if_i}$ = 4 + 10 + 24 + 40 + 15 = 93

and, ∑$\bf{f_i}$ = 4 + 5 + 8 + 10 + 3 = 30

∴ $\bf\overline{x}$ = ∑$\bf{x_if_i}$/∑$\bf{f_i}$ = $\frac{93}{30} = \frac{31}{10} = 3.1$

$\large \bold{Hence,\:the\:mean\:of\:the\:given\:data\:is\:3.1}$

$\fbox{\LARGE{\underline{\underline{\bf{More\:to\:know:}}}}}$

The mean is expressed as $\bf\overline{x}$

The formula of mean is ∑$\bf{x_if_i$/∑$\bf{f_i$