Question

Find the mean proportion :- 72 And 98

Answer 1

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• First number (a) = 72

• Second number (b) = 98

★ We know that -

For two numbers a & b -

$\sf\boxed{mean \: proportion =\sqrt{ab}}$

★ mean proportion of 72 & 98 -

$\sf{=\sqrt{72\times 98}}$

$\sf{=\sqrt{(36\times 2)\times (2\times 49)}}$

$\sf{=\sqrt{36\times 4\times 49}}$

$\sf{=\sqrt{6^{2}\times 2^{2}\times 7^{2}}}$

$\sf{=\sqrt{(6\times 2\times 7)^{2}}}$

$\sf{=\sqrt{84^{2}}}$

$\sf{= 84^{(2\times \dfrac{1}{2})}}$

$\sf{= 84^{1}}$

$\sf{= 84}$

Mean proportion of 72 and 98 is 84.