Question

find the mean proportion between 1/25 and 1/16​

Answer 1

Let 'b' be the mean proportion of 1/25 and 1/16

Therefore,

b^2 = 1/25×1/16

b =

$\sqrt{ \frac{1}{25 } } \times \sqrt{ \frac{1}{16} }$

b =

$\sqrt{ \frac{1}{25 \times 16} }$

b =

$\sqrt{ \frac{1}{400} }$

b =

$\frac{1}{20}$

Therefore the geometric mean of 1/25 and 1/16 is 1/20

Answer 2

Answer

1/20 is the mean proportion of 1/25 and 1/16