Question

find the mean proportion of c x cube by a b square and a by CX

Answer 1

$we \: know \: that \\ \: \\ mean \: proportion \: of \:t wo \: numbers \: = \sqrt{ab} \\ \\ where \: a = \frac{cx {}^{3} }{ab {}^{2} } \\ \\ and \\ \\ b = \frac{a}{cx} \\ \\ now \: \sqrt{ab} = \sqrt{ \frac{c {x}^{3} }{ab {}^{2} } \times \frac{a}{cx} } \\ \\ = \sqrt{ \frac{ {x}^{2} }{b {}^{2} } } = \frac{x}{b} \\ \\ thus \: \: mean \: proportion \: of \: two \: numbers \: = \frac{x}{b} \\ \\ hope \: this \: helps \: you$
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Answer 2

Answer:

Step-by-step explanation: