find the mean proportion of (x-y)*(x³-x²y)
Answers
Answered by
0
Step-by-step explanation:
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Answered by
1
Step-by-step explanation:
Let the mean proportional to (x–y) and (x
3
–x
2
y) be n.
(x–y),n,(x
3
–x2
y
) are in continued proportion
(x–y):n=n:(x
3
–x
2
y)
n
2
=(x−y)(x
3
–x
2
y)
n
2
=(x−y)x
2
(x–y)
n
2
=x
2
(x–y)
2
n=x(x–y)
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