Question

Find the mean proportion to :
(i) 1 /25 and 1/16​

Answer 1

Answer:

Let 'b' be the mean proportion of 1/25 and 1/16

Therefore,

b^2 = 1/25×1/16

b =

\sqrt{ \frac{1}{25 } } \times \sqrt{ \frac{1}{16} }

25

1

×

16

1

b =

\sqrt{ \frac{1}{25 \times 16} }

25×16

1

b =

\sqrt{ \frac{1}{400} }

400

1

b =

\frac{1}{20}

20

1

Therefore the geometric mean of 1/25 and 1/16 is 1/20

Answer 2

Answer:

mean proportion between 1/4 and 1/25 is 1/10.

Step-by-step explanation:

mean proportion is sqrt of (1/4*1/25)

=(1/2*1/5)

=1/10

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