Question

find the measure of AC​

Answer 1

Answer:

let E be the point where a Line extended from B meets AC now

(EC)² + (BE)² = (BC)²

(EC)² = (BC)² - (BE)²

= 12² - 4² = 144 - 16 = 128

so EC = √128 = 11.3137

now AC = AE + EC = 3 + 11.3137 = 14.3137

Answer 2

Answer:

AC=14.313

Step-by-step explanation:

Given-

AB=5 ; AD=3 ; BC=12 and BD=4

now,

In right-angle ΔBDC , ∠BDC=90°

then, by pythagoras theorem

H²=P²+B²

(BC)²=(BD)²+(DC)²

(12)²=4²+(DC)²

144=16+(DC)²

144-16=(DC)²

(DC)²=128

DC=√128

DC=11.313

∵AC=AD+DC

 AC=3+11.313

 AC=14.313