find the measure of AC and AB
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Answer:
25^2= 15^2 + ac^2
ac^2 = 25^2 - 15^2
ac^2 = 625-225
ac^2 = 400
ac = 20
ab^2 = 36^2 + 20^2
ab^2 = 1296 + 400
ab^2 = 1696
ab = 41.18 (approx)
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given:ABC is a triangle AD perpendicular to BC
BD=21cm
CD=15cm
BC=BD+CD=21+15=36cm
by the Pythagoras theorem
in ADC triangle
AD square =AC square+CD square
25×25=AC square+15×15
625=AC square+225
625-225=AC square
400=AC square
root 400=AC
20=AC
by the Pythagoras theorem
in ABC triangle
AB square=BC square +AC square
AB square=36 square+20square
AB square=1296+400
AB square=1696
AB= root 1696
AB =41.18c.m
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