Find the measure of all angles of a parallelogram, if one angle is 24°less than the twice of the smallest angle?
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let one angle be x .then the other angle is 2x-24
Given that,
=> x+x+2x-24+2x-24=360
=> 6x-48=360
=> 6x=408
=> x=68
so the angles of the parallogram are 68,68,112,112
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Given that,
=> x+x+2x-24+2x-24=360
=> 6x-48=360
=> 6x=408
=> x=68
so the angles of the parallogram are 68,68,112,112
plz mark as brainliest.
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