Question

FIND THE MEASURE OF ALL THE ANGLES GIVEN IN THE FIGURE ​

Answer 1

Step-by-step explanation:

( 2x + 30° ) + ( 3x - 80° ) + ( x - 10° ) = 180°

( 2x + 3x + x ) + ( 30° - 80° - 10° ) = 180°

6x - 60° = 180°

6 ( x - 10 )° = 180°

x - 10° = 180° / 6

x - 10° = 30°

x = 30° + 10°

× = 40°

Therefore;

angle ACD = 2x+30° = 2×40°+30° = 80°+30° = 110°

angle DCE = 3x-80° = 3×40°-80° = 120°-80° = 40°

angle ECB = x-10° = 40°-10° = 30°

Answer 2

answer

=> 2x + 30 + 3x - 80 + x - 10 = 180

=> 2x + 3x + x = 180 - 30 + 80 + 10

=> 6x = 180 - 30 + 80 + 10

=> 6x = 150 + 80 + 10

=> 6x = 240

=> x = 240 / 6

=> x = 40

measures

a) 2x + 30

=> 2*40 + 30

=> 80 + 30

=> 110

b) 3x - 80

=> 3*40 - 80

=> 120 - 80

=> 40

c) x - 10

=> 40 - 10

=> 30

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