Find the measure of all the angles of a parallelogram, if one angle is 24° less than the twice
of the smallest angle.
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Answer:
Let x
∘
be the smallest angle of the parallelogram.
According to the question, the largest angle is (2x
∘
−24
∘
).
It is known that the sum of the adjacent angles of the parallelogram is 180
∘
. Then,
x
∘
+2x
∘
−24
∘
=180
∘
3x
∘
=180
∘
+24
∘
3x
∘
=204
∘
x
∘
=68
∘
Therefore, the largest angle is (2(68
∘
)−24
∘
)=112
∘
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