Math, asked by ksuryamanoharff, 1 month ago

Find the measure of all the angles of a parallelogram, if one angle is 24° less than the twice
of the smallest angle.

Answers

Answered by vaheeda2000
1

Answer:

Let x

be the smallest angle of the parallelogram.

According to the question, the largest angle is (2x

−24

).

It is known that the sum of the adjacent angles of the parallelogram is 180

. Then,

x

+2x

−24

=180

3x

=180

+24

3x

=204

x

=68

Therefore, the largest angle is (2(68

)−24

)=112

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