Question

find the measure of all the angles of a parallelogram if one angle is 12°loss the twice of the smallest angle

Answer 1

let one angle be x and another angle be 2x -12

As we know the adjacent angles are supplementary

x+2x-12=180

3x-12=180

3x=180-12

3x= 168

x=168/3

x=56

another angle= 2(56)-12

= 112-12

= 100

we know that opposite angles are equal.

The four angles are 56,56,100,100