Math, asked by unknown1172, 9 months ago

Find the measure of an angel, if six times it's complement is 120° less than twice it's supplement.
Needed with full explanation. Don't copy from net otherwise I will report it.​

Answers

Answered by sakshiattri16
1

Answer:

let angle be x

complement 90−x

supplement 180−x

6(90−x)=2(180−x)−12 {Given}

540−6x=360−2x−12

180−12 = 4x

x=42

Step-by-step explanation:

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Answered by SarcasticL0ve
0

Correct Question:

  • Find the measure of an angle, if six times it's complement is 12° less than twice it's supplement.

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AnswEr:

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⋆ Let the angle be x.

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⋆ whose Complement = 90 - x

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⋆ whose Supplement = 180 - x

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According to question,

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Six times complement of angle is 12° less than twice it's supplement.

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:\implies\sf 6(90^\circ - x) = 2(180^\circ - x) - 12^\circ

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:\implies\sf 540 - 6x = 360 - 2x - 12

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:\implies\sf 540 - 6x =  348 - 2x

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:\implies\sf 540 - 348 = -2x + 6x

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:\implies\sf 192 = 4x

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:\implies\sf x = \cancel{ \dfrac{192}{4}}

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:\implies\bf \red{x = 48^\circ}

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\therefore The measure of angle is 48°

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