find the measure of an angle if 3 times its supplement is 60 degree more than 6 times its complement
Answers
Answered by
32
Hi...
let the angle be x
3(180-x)=6(90-x)+60
540-3x=540-6x+60
-3x+6x=60
3x=60
x=20
Angle=20°
let the angle be x
3(180-x)=6(90-x)+60
540-3x=540-6x+60
-3x+6x=60
3x=60
x=20
Angle=20°
sethiankush192pd78bl:
Hlo Thnx for helping me out
Answered by
0
Answer:
3(180-x) = 6(90-x) + 60
=> 540 - 3x = 540 - 6x + 60
=> 6x - 3x = 60
=> 3x = 60
=> x = 60/3
=> x = 20
So the angle is 20
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