find the measure of an angle if 7times its complement is 10° less than 3 times its supplement
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let the angle be x
measure of its complement = (90-x)
measure of its supplement = (180-x)
7(90-x) = 3(180-x)-10
630-7x = 540-3x-10
630-7x = 530-3x
-7x+3x = 530-630
-4x = -100
x = -4/-100
x = 25
measure of its complement = (90-x)
measure of its supplement = (180-x)
7(90-x) = 3(180-x)-10
630-7x = 540-3x-10
630-7x = 530-3x
-7x+3x = 530-630
-4x = -100
x = -4/-100
x = 25
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