Question

Find the measure of an angle if it is 20°less than twice of its complement.

Answer 1

Answer:

Given:

Find the angle if six times of its complement 12 degree less than twice of its supplement?

Solution:

Let the angle be x

Complement = 90 – x

Supplement = 180 – x

Given 6 (90 – x) + 12 = 2 (180 – x)

X = 48 degrees.  

Answer 2

Answer:

If the measure of one angle is 20 more than 2 times that of the other, then what is the measurement of the two angles if the angles are supplementary?

Let A and B be two angles.

A = 2B+20 [as per question] ——— ———- —-(1)

Since A and B are supplementary angles, A + B = 180 deg

So, A= 180 - B ————————— ——————-(2)

Substituting value A in eqn (1) , we get-

180-B = 2B + 20

or, 180 = 3B +20 [adding B to both sides]

or, 3 B = 180–20 = 160

So, B = 160/3 deg ————————————(3)

A = 2B+20 = 2 . 160/3 + 20 ( putting vale of B from eqn(3)]

A = 320/3 + 20 = 380/3 deg

Thus measures of angles, A = 380/3 deg and B = 160/3 deg. ANS.