Question

find the measure of an angle if its supplement measures 39 degrees more than twice its complement​

Answer 1

$\huge \bf{GIVEN}$

✥find the measure of an angle if its supplement measures 39 degrees more than twice its complement

$\sf{let \: angle \: be \: x}$

$\sf{supplementary \: will \: be \: = 180 - x}$

$\sf{and \: complemantary \: will \: be \: 90 - x}$

so

given supplement will be equal to conplemantary +39

$\rm \red{180 - x = 2(90 - x) + 39}$

$\rm \blue{2x - x = 180 - 180 + 39}$

$\rm \pink{x = 39}$

$\bf{ \huge{ \boxed{ \red{ \tt{x = 39 \: }}}}}$

Answer 2

Answer:

★ 39° ★

Step-by-step explanation:

Given:

• Measure of supplement is 39° more than twice it's complement.

To Find:

• What is the measure of angle?

Solution: Let the measure of angle be x°

∴ It's Supplement will be = (180 – x)° and Complement will be = (90 – x)°

A/q

$\small\implies{\sf }$ (180 – x)° = 2 (90 –x)° + 39°

$\small\implies{\sf }$ (180 – x)° = 180° – 2x + 39

$\small\implies{\sf }$ 180 – x = 219 – 2x

$\small\implies{\sf }$ 180 – 219 = – 2x + x

$\small\implies{\sf }$ – 39 = –x

$\small\implies{\sf }$ 39° = x

Hence, The measure of angle is x° = 39°