Find the measure of an angle if seven times it's complement is 10°less than 3 times it's supplement
Answers
Answered by
30
Answer:
Hello❇❤!!
Let angle= x
Measure of its complement=(90-x)
Measure of its supplement=(180-x)
7(90-x)=3(180-x)-10
630-7x=540x-3x-10.
-7x+3x=530-630
-4x=-100
x=100/4
x=25 degree
________________________
Thanks❇❤!!
Answered by
19
Let the required angle be x°
complement=90°-x°
supplement=180°-x°
A/Q
7(90°-x)=3(180°-x°)-10
630°-7x=540°-3x-10
630-540+10=-3x+7x-
100°=4x
100°/4=x
25°=x
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