Question

Find the measure of an angle, if seven times its complement is 10° less than three times its supplement.​

Answer 1

Answer:

Let the angle be x

Let the angle be xmeasure of its complement = (90-x)

Let the angle be xmeasure of its complement = (90-x)measure of its supplement= (180-x)

Let the angle be xmeasure of its complement = (90-x)measure of its supplement= (180-x)7(90-x) =3(180-x)-10

Let the angle be xmeasure of its complement = (90-x)measure of its supplement= (180-x)7(90-x) =3(180-x)-10630 - 7x=540x-3x -10

Let the angle be xmeasure of its complement = (90-x)measure of its supplement= (180-x)7(90-x) =3(180-x)-10630 - 7x=540x-3x -10-7x+3x= 530-630

Let the angle be xmeasure of its complement = (90-x)measure of its supplement= (180-x)7(90-x) =3(180-x)-10630 - 7x=540x-3x -10-7x+3x= 530-630-4x=-100

Let the angle be xmeasure of its complement = (90-x)measure of its supplement= (180-x)7(90-x) =3(180-x)-10630 - 7x=540x-3x -10-7x+3x= 530-630-4x=-100x= 100/4

Let the angle be xmeasure of its complement = (90-x)measure of its supplement= (180-x)7(90-x) =3(180-x)-10630 - 7x=540x-3x -10-7x+3x= 530-630-4x=-100x= 100/4x=25

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