find the measure of an angle if seven times its complement is 10*less than three times its supplement
Answers
Answered by
181
Hey
here is your answer,
Let the measure of the required angle be x°.
Then, the measure of its complement =(90−x)°.
And the measure of its supplement=(180−x)°.
Therefore,
7(90−x)=3(180−x)−10
⇒630−7x=540−3x−10
⇒4x=100
⇒x=25
Hence, the measure of the required angle is 25°.
Hope it helps you!
here is your answer,
Let the measure of the required angle be x°.
Then, the measure of its complement =(90−x)°.
And the measure of its supplement=(180−x)°.
Therefore,
7(90−x)=3(180−x)−10
⇒630−7x=540−3x−10
⇒4x=100
⇒x=25
Hence, the measure of the required angle is 25°.
Hope it helps you!
Answered by
78
let the angle be =x
therefore, (3*(180-x)) - (7*(90-x)) = 10.
or 540 - 3x - (630-7x) = 10
or 540 - 3x - 630 + 7x = 10
or 4x - 90 = 10
or 4x = 10 + 90
or 4x = 100
or x = 100/4
x = 25
Hence the angle is 25 degrees.
therefore, (3*(180-x)) - (7*(90-x)) = 10.
or 540 - 3x - (630-7x) = 10
or 540 - 3x - 630 + 7x = 10
or 4x - 90 = 10
or 4x = 10 + 90
or 4x = 100
or x = 100/4
x = 25
Hence the angle is 25 degrees.
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