Find the measure of an angle, if six times of its complement is 12c less than twice ofits supplement.
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Answered by
4
Let the angle be 90-x .
It's supplement is 90 + x
It's complement is x
Given,
6 ( x) +12 = 2 ( 90+ x)
6x +12 = 180 + 2x
4x = 168 .
x = 42 .
Therefore the angle is 90-42 = 48 .
Hope this helps!
It's supplement is 90 + x
It's complement is x
Given,
6 ( x) +12 = 2 ( 90+ x)
6x +12 = 180 + 2x
4x = 168 .
x = 42 .
Therefore the angle is 90-42 = 48 .
Hope this helps!
Answered by
2
Hey!
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Let compliment be x
Let it's supplement be 90-x
Let angle be 90-x
A.T.Q
6 (x) + 12 = 2 (90+x)
6x+12= 180+2x
6x-2x= 180-12
4x= 168
x= 42
Angle measure = 90-42=48°
_____________________
Hope it helps...!!!
_____________________
Let compliment be x
Let it's supplement be 90-x
Let angle be 90-x
A.T.Q
6 (x) + 12 = 2 (90+x)
6x+12= 180+2x
6x-2x= 180-12
4x= 168
x= 42
Angle measure = 90-42=48°
_____________________
Hope it helps...!!!
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