Question

Find the measure of an angle that is half as large as its complement.

Answer 1

Step-by-step explanation:

→ let angles be x ,x/2,

→ since angles are complementary

→ sum of two angles is 90 degrees

→ x+x/2=90

→ 3x=180

→ x=60

→ Angles are 60,30.

Answer 2

Question:

Find the measure of an angle that is half as large as it's complement

To Find:

measure of the angle

Solution:

we know that:

${\boxed{ \sf{ \orange{complementary \: angles \: = 90 \degree}}}}$

Let "x" be the angle

then it's complementary angle = $\sf{ 90 - x}$

It is given that,

the angle is half as long as it's complement

So,

$\implies\sf{x = \frac{1}{2}(90-x) [multiply\:by\:2]}$

$\implies\sf{ 2x = 90 - x [move\:x\: to\:left\:side]}$

$\implies\sf{ 3x = 90}$

$\implies\sf{ x = \frac{90}{3}}$

$\implies\sf{ x = 30°}$

Hence,

the angle is 30°