Question

find the measure of an angle which is 14 degree less than three times its complement plzz answer

Answer 1

Answer:

71

Step-by-step explanation:

let the angle be x

complementary angle = 90-x

x-14=3(90-x)

x+3x=270+14

4x=284

x =284/4

=71

plz mark me as brainliest if correct

Answer 2

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

The angles are 83° and 7°.

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

Given :

The angle is 14 degree less than three times its complement

To find :

The Measures of the angles

Solution :

The angles are Complementary angles, that means these angles sum up and make 90°.

Consider -

• One Angle as x
• Second angle as 3(90 - x) - 14

★ $\boxed{\bf{x+3(90-x)-14=90}}$

$\longrightarrow$ x + 3(90 - x) - 14 = 90

$\longrightarrow$ x + 270 - 3x - 14 = 90

$\longrightarrow$ -2x + 270 - 14 = 90

$\longrightarrow$ -2x + 256 = 90

$\longrightarrow$ -2x = 90 - 256

$\longrightarrow$ -2x = -166

$\longrightarrow$ x = -166/-2

$\longrightarrow$ x = 83

One angle = 83°

$\rule{300}{1.5}$

★ Value of 3(90 - x) - 14

$\longrightarrow$ 3(90 - 83) - 14

$\longrightarrow$ 270 - 249 - 14

$\longrightarrow$ 21 - 14

$\longrightarrow$ 7

Second angle = 7°

$\therefore$ The angles are 83° and 7°.

$\rule{300}{1.5}$

$\mathfrak{\large{\underline{\underline{Verification :-}}}}$

Check if their sum is 90° or not.

$\longrightarrow$ 83 + 7

$\longrightarrow$ 90

$\therefore$ The angles are 83° and 7°.